This is aptitude questions and answers section on Simple Equations with the explanation for various interview, competitive examinations, and entrance tests. Learn and practice Simple Equations quiz in maths through the below provided questions and answers.
## Simple Equations Questions - Simple Equations Quiz Details

Online Test Name |
Simple Equations |

Exam Type |
Multiple Choice Questions |

Category |
Aptitude Quiz |

Number of Questions |
30 |

1. Solve the equation for x : 6x - 27 + 3x = 4 + 9 - x
### Workspace

### Report Error

2. Solve the equation for x : 19(x + y) + 17 = 19(-x + y) - 21
### Answer & Explanation

### Workspace

### Report Error

Answer: Option A

Explanation:

19x + 19y + 17 = -19x + 19y - 21

38x = -38 => x = -1

3. The cost of 2 chairs and 3 tables is Rs.1300. The cost of 3 chairs and 2 tables is Rs.1200. The cost of each table is more than that of each chair by?
### Answer & Explanation

### Workspace

### Report Error

Answer: Option E

Explanation:

2C + 3T = 1300 --- (1)

3C + 3T = 1200 --- (2)

Subtracting 2nd from 1st, we get

-C + T = 100 => T - C = 100

4. The denominator of a fraction is 1 less than twice the numerator. If the numerator and denominator are both increased by 1, the fraction becomes 3/5. Find the fraction?
### Answer & Explanation

### Workspace

### Report Error

Answer: Option D

Explanation:

Let the numerator and denominator of the fraction be 'n' and 'd' respectively.

d = 2n - 1

(n + 1)/(d + 1) = 3/5

5n + 5 = 3d + 3

5n + 5 = 3(2n - 1) + 3 => n = 5

d = 2n - 1 => d = 9

Hence the fraction is : 5/9.

5. The cost of 10 kg of apples is equal to the cost of 24 kg of rice. The cost of 6 kg of flour equals the cost of 2 kg of rice. The cost of each kg of flour is Rs.20.50. Find the total cost of 4 kg of apples, 3 kg of rice and 5 kg of flour?
### Answer & Explanation

### Workspace

### Report Error

Answer: Option B

Explanation:

Let the costs of each kg of apples and each kg of rice be Rs.a and Rs.r respectively.

10a = 24r and 6 * 20.50 = 2r

a = 12/5 r and r = 61.5

a = 147.6

Required total cost = 4 * 147.6 + 3 * 61.5 + 5 * 20.5

= 590.4 + 184.5 + 102.5 = Rs.877.40